Five equal resistances each of resistance R are connected as shown in the figure. A battery of V volts is connected between A and B. The current flowing in AFCEB will be:
Text Solution
Verified by ExpertsC
The given circuit can be redrawn as shown. From circuit,
= 
= 1
Thus, it is balanced Wheastone's bridge, so resistance in arm CD is ineffective and so, current do not flows in this arm.
Net resistance of the circuit is
= 
+ 
= 
+ 
= 
= 
∴ R' = R
So, net current drawn from the battery
i' = 
= 
As from symmetry, upper circuit AFCEB is half of the whole circuit and is equal to AFDEB. So, in both the halves half of the total current will flow.
Hence, in AFCEB, the current flowing is
i = 
= 
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems